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What mass must suspended from the free e...

What mass must suspended from the free end of a steel wire of length 2m and diameter 1mm to stretch it by 1mm ? `(Y=2xx10^(11)Nm^(-2))`

Text Solution

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`r=(1)/(2)xx10^(-3)m, L=2m, Y=(Mg)/(pi r^(2)) (L)/(e )`
`M=(Y(pi r^(2))e)/(gL)=(2xx10^(11)xxpi ((1)/(2)xx10^(-3))^(2)xx1xx10^(-3))/(9.8xx2)`
`=(pi xx10^(2))/(9.8xx4)=(100pi)/(39.2)=8.015kg`
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