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A 5.0 cm cube of substance has its up...

A 5.0 cm cube of substance has its upper face displaced by 0.65 cm, by a tangential force of 0.25 N. Calculate the modulus of rigidity of rigidity of the substance.

Text Solution

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`G=(FL)/(Al), A=L^(2) , G=(FL)/(L^(2)l)=(F)/(Ll)`
Here, `L=5.0xx10^(-2)m`
`l=0.65xx10^(-2)m, F=0.25N`.
`G=(0.25)/(5.0xx10^(-2) xx 0.65xx10^(-2)) =(0.25 xx 10^(4))/(3.25)`
`=769.2Nm^(-2)`
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