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Calculate the force .F. needed to punch...

Calculate the force .F. needed to punch a 1.46cm diameter hole in a steel plate 1.27 cm thick (as shown in fig). The ultimate shear strength of steel is 345 M `N//m^(2)`

Text Solution

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As in punching, shear elasticity is involved, the hole will be punched it
`((F_(11))/(A)) gt` ultimate shear stress
`F_(11) gt ` (shear stress ) X Area
`F_(11)` min `=(3.45xx10^(8))(2pi rL)(A=2pirL)`
`=(3.45xx10^(8)) (2xx3.14)xx0.73xx10^(-2) xx 1.27 xx 10^(-2)`
`=200KN`
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