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When a rubber ball of volume V, bulk m...

When a rubber ball of volume V, bulk modulus .K. is taken to a depth .h. in water, then decrease in its volume is

Text Solution

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`B=(DeltaP)/((-(DeltaV)/(V)))`
`-DeltaV=((DeltaP)V)/(K)`
`=(h rho g V)/(K)`
So decrease in volume of ball `=(h rho g V)/(K)`
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