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An aluminium rod has a breaking strain 0...

An aluminium rod has a breaking strain 0.2%. The minimum cross-sectional area of the rod in `m^2` in order to support a load of `10^4N` is if Youngs modulus is `7 xx 10^9 Nm^(-2)`

A

`1.7xx10^(-4)`

B

`1.7xx10^(-3)`

C

`7.1xx10^(-4)`

D

`1.4xx10^(-4)`

Text Solution

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The correct Answer is:
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