Given the density of the chloroform is `1.510gcm^-3` , then the volume occupied by 20.050 g of chloroform (upto correct significant figures) is

Options

A. `13.3cm^3`
B. `13.278cm^3`
C. `13.28cm^3`
D. `13.2780cm^3`

Answer

To find the volume occupied by 20.050 g of chloroform given its density of 1.510 g/cm³, we can use the formula for volume:

### Step-by-Step Solution:

1. **Identify the formula for volume**:
The formula to calculate volume (V) from mass (m) and density (d) is:
\[ V = \frac{m}{d} \]

2. **Substitute the values**:
Here, the mass (m) of chloroform is 20.050 g and the density (d) is 1.510 g/cm³. We substitute these values into the formula:
\[ V = \frac{20.050 \, \text{g}}{1.510 \, \text{g/cm}^3} \]

3. **Perform the calculation**:
Calculate the volume:
\[ V = \frac{20.050}{1.510} \approx 13.2781 \, \text{cm}^3 \]

4. **Determine significant figures**:
The mass (20.050 g) has 5 significant figures, and the density (1.510 g/cm³) has 4 significant figures. The result should be reported with the least number of significant figures, which is 4 in this case.

5. **Round the result**:
The calculated volume is 13.2781 cm³. We round this to 4 significant figures:
- The first four digits are 13.27. The next digit is 8, which means we round up.
- Therefore, we round 13.27 to 13.28 cm³.

### Final Answer:
The volume occupied by 20.050 g of chloroform is **13.28 cm³**.

---