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A compound was found of contain 14.34% o...

A compound was found of contain 14.34% oxygen. The minimum molecular weight of the compound is

A

111.5 g

B

223.15 g

C

97.62 g

D

195.26 g

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The correct Answer is:
To find the minimum molecular weight of the compound containing 14.34% oxygen, we can follow these steps: ### Step 1: Determine the mass percentage of oxygen We know that the compound contains 14.34% oxygen by mass. ### Step 2: Calculate the mass of oxygen in 100 g of the compound If we assume we have 100 g of the compound, then the mass of oxygen in the compound would be: \[ \text{Mass of oxygen} = 14.34 \, \text{g} \] ### Step 3: Use the molar mass of oxygen The molar mass of oxygen (O) is approximately 16 g/mol. ### Step 4: Calculate the moles of oxygen in the compound To find the number of moles of oxygen in the compound, we can use the formula: \[ \text{Moles of oxygen} = \frac{\text{Mass of oxygen}}{\text{Molar mass of oxygen}} \] Substituting the values: \[ \text{Moles of oxygen} = \frac{14.34 \, \text{g}}{16 \, \text{g/mol}} = 0.89625 \, \text{mol} \] ### Step 5: Determine the total mass of the compound The total mass of the compound is 100 g (as we assumed). ### Step 6: Calculate the mass of the other elements in the compound The mass of the other elements in the compound can be calculated as: \[ \text{Mass of other elements} = \text{Total mass} - \text{Mass of oxygen} \] Substituting the values: \[ \text{Mass of other elements} = 100 \, \text{g} - 14.34 \, \text{g} = 85.66 \, \text{g} \] ### Step 7: Calculate the minimum molecular weight of the compound The minimum molecular weight of the compound can be calculated by considering the total mass of the compound and the moles of oxygen. Since the mass of the compound is 100 g and we have calculated the moles of oxygen, we can use the following relation: \[ \text{Minimum Molecular Weight} = \frac{\text{Total mass of the compound}}{\text{Moles of oxygen}} \] Substituting the values: \[ \text{Minimum Molecular Weight} = \frac{100 \, \text{g}}{0.89625 \, \text{mol}} \approx 111.5 \, \text{g/mol} \] ### Conclusion The minimum molecular weight of the compound is approximately **111.5 g/mol**.
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