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Let the mass of electron is two times, m...

Let the mass of electron is two times, mass of proton is `1/4^(th)` and mass of neutron is 3/2 of original mass. Then, the atomic weight of `6^(C^12)` atom

A

Increases by 37.5%

B

Decreases by 87.5%

C

Decreases by 12.5%

D

Remains same

Text Solution

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The correct Answer is:
To solve the problem, we need to calculate the atomic weight of the carbon-12 atom given the modified masses of the particles (protons, neutrons, and electrons). ### Step-by-Step Solution: 1. **Identify the Original Masses:** - The original mass of a proton (m_p) is approximately 1 amu. - The original mass of a neutron (m_n) is approximately 1 amu. - The original mass of an electron (m_e) is negligible (approximately 0.0005 amu). 2. **Modified Masses:** - According to the problem: - Mass of electron = 2 * original mass of proton = 2 * 1 amu = 2 amu. - Mass of proton = 1/4 * original mass of proton = 1/4 * 1 amu = 0.25 amu. - Mass of neutron = 3/2 * original mass of neutron = 3/2 * 1 amu = 1.5 amu. 3. **Calculate Total Mass of Carbon-12:** - Carbon-12 has 6 protons and 6 neutrons. - Total mass from protons = 6 * mass of proton = 6 * 0.25 amu = 1.5 amu. - Total mass from neutrons = 6 * mass of neutron = 6 * 1.5 amu = 9 amu. - Total atomic mass of Carbon-12 = Total mass from protons + Total mass from neutrons = 1.5 amu + 9 amu = 10.5 amu. 4. **Calculate the Decrease in Mass:** - Original atomic mass of Carbon-12 = 12 amu. - Decrease in mass = Original mass - New mass = 12 amu - 10.5 amu = 1.5 amu. 5. **Calculate Percentage Decrease:** - Percentage decrease = (Decrease in mass / Original mass) * 100 - Percentage decrease = (1.5 amu / 12 amu) * 100 = 12.5%. ### Final Answer: The atomic weight of the modified Carbon-12 atom is 10.5 amu, and the percentage decrease in mass is 12.5%.
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Knowledge Check

  • It is known that atom contain protons. Neutrons and electrons. If the mass of neutron is assumed to half of its orginal value where as that of proton is assumed to be twice of its original value then the atomic mass of ._(6)^(14)C will be :-

    A
    same
    B
    `25%` more
    C
    `14.28%` more
    D
    `28.5%` more

  • It is known that an atom contains protons, neutrons and almost electrons. If the mass of neutron is assumed to half of its original value where as that of proton is assumed to be twice of its original value then the atomic mass of _(7)^(14)N will be :-

    A
    same
    B
    `25%`more
    C
    `14.28%`more
    D
    `28.5%` less

  • The mass of an atom is due to the masses of protons and neutrons in the nucleus. The relative masses of protons and neutrons are almost equal to one. Therefore, the atomic mass of an element should be nearly a whole number. But in many cases the atomic masses are fractional. The main reason for these fractional atomic masses is that these elements occur in nature as a mixture of several isotopes. The atomic mass of an element is the average of the atomic masses of these isotopes in the ratio of their proportion of occurrence. The fractional atomic masses of elements are due to the existence of

    A
    isotopes having different masses
    B
    diagonal relationship
    C
    equal number of electrons and protons
    D
    none of these.

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