among the following representation of excited state of atoms, which one is impossible

Options

A. `3s^1 3p^1`
B. `[Ne]3s^2 3p^6 4s^3 3d^2`
C. `1s^2 2s^2 2p^(7)3s^2`
D. `[Ne]3s^2p^3d^1`

Answer

To solve the question about which representation of excited states of atoms is impossible, we need to analyze the electronic configurations provided in the options.

### Step-by-Step Solution:

1. **Understanding Electron Configuration**:
- Each atomic orbital can hold a specific maximum number of electrons:
- S orbital can hold a maximum of 2 electrons.
- P orbital can hold a maximum of 6 electrons.
- D orbital can hold a maximum of 10 electrons.
- F orbital can hold a maximum of 14 electrons.

2. **Analyzing Each Option**:
- **Option 1: 3S¹ 3P¹**
- Here, the S orbital has 1 electron and the P orbital has 1 electron. This configuration is possible since it does not exceed the maximum capacity of the orbitals.

- **Option 2: 3S³**
- The S orbital cannot hold more than 2 electrons. Therefore, having 3 electrons in the 3S orbital is impossible.

- **Option 3: 3P⁷**
- The P orbital cannot hold more than 6 electrons. Therefore, having 7 electrons in the 3P orbital is also impossible.

- **Option 4: 3P³ 3D¹ 3S²**
- This configuration is possible as it adheres to the maximum electron limits of the respective orbitals.

3. **Identifying Impossible Configurations**:
- From the analysis, we can conclude that:
- Option 2 (3S³) is impossible.
- Option 3 (3P⁷) is also impossible.

### Conclusion:
The impossible representations of excited states of atoms are **Option 2 (3S³)** and **Option 3 (3P⁷)**.