In the general electronic configuration `(n-2)^f(1-14)` `(n-1)^d(0-1) ns^2`,if the value of n=7,the configuration will be of

Options

A. Lanthanoids
B. Actinides
C. Transition elements
D. p-block elements

Answer

To solve the question, we need to determine the electronic configuration based on the given general electronic configuration and the value of n.

### Step-by-Step Solution:

1. **Identify the given general electronic configuration**:
The general electronic configuration provided is \((n-2)^f(1-14)(n-1)^d(0-1) ns^2\).

2. **Substitute the value of n**:
We are given that \(n = 7\). We will substitute this value into the electronic configuration.
- For \(n-2\): \(7-2 = 5\)
- For \(n-1\): \(7-1 = 6\)

Therefore, the electronic configuration becomes:
\[ (5)^f(1-14)(6)^d(0-1)(7)s^2 \]

3. **Interpret the configuration**:
The configuration can be rewritten as:
\[ (5f)(1-14)(6d)(0-1)(7s^2) \]
This indicates that we are dealing with an f-block element (since it has \(5f\)).

4. **Determine the type of f-block element**:
The f-block elements are divided into two series:
- Lanthanides (4f series) which correspond to \(n-2\) being 4 (when \(n=6\)).
- Actinides (5f series) which correspond to \(n-2\) being 5 (when \(n=7\)).

Since we have \(5f\), this indicates that the element is part of the actinide series.

5. **Conclusion**:
Therefore, the electronic configuration corresponds to an actinide element.

### Final Answer:
The configuration will be of an actinide element.

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