The species having bond order same as that of
(a)` CO`
(b) `O_2`
(c)`N_2`
(d) `H_2`

Options

A. (a) and(b)
B. (a) and(c)
C. (c) and(d)
D. (a), (b) and(d)

Answer

To determine the species having the same bond order as the given molecules (CO, O2, N2, H2), we first need to calculate the bond order for each of these species.

### Step-by-Step Solution:

1. **Calculate the Bond Order of CO (Carbon Monoxide)**:
- CO has a total of 10 electrons (6 from Carbon and 4 from Oxygen).
- The molecular orbital configuration for CO is:
\[ \sigma(1s)^2 \sigma^*(1s)^2 \sigma(2s)^2 \sigma^*(2s)^2 \sigma(2p_z)^2 \pi(2p_x)^2 \pi(2p_y)^2 \]
- The bond order is calculated using the formula:
\[ \text{Bond Order} = \frac{(N_b - N_a)}{2} \]
where \(N_b\) is the number of bonding electrons and \(N_a\) is the number of antibonding electrons.
- For CO, \(N_b = 10\) and \(N_a = 2\):
\[ \text{Bond Order} = \frac{(10 - 2)}{2} = 4 \]

2. **Calculate the Bond Order of O2 (Oxygen)**:
- O2 has a total of 16 electrons (8 from each Oxygen).
- The molecular orbital configuration for O2 is:
\[ \sigma(1s)^2 \sigma^*(1s)^2 \sigma(2s)^2 \sigma^*(2s)^2 \sigma(2p_z)^2 \pi(2p_x)^2 \pi(2p_y)^1 \]
- For O2, \(N_b = 10\) and \(N_a = 6\):
\[ \text{Bond Order} = \frac{(10 - 6)}{2} = 2 \]

3. **Calculate the Bond Order of N2 (Nitrogen)**:
- N2 has a total of 14 electrons (7 from each Nitrogen).
- The molecular orbital configuration for N2 is:
\[ \sigma(1s)^2 \sigma^*(1s)^2 \sigma(2s)^2 \sigma^*(2s)^2 \sigma(2p_z)^2 \pi(2p_x)^2 \pi(2p_y)^2 \]
- For N2, \(N_b = 10\) and \(N_a = 2\):
\[ \text{Bond Order} = \frac{(10 - 2)}{2} = 4 \]

4. **Calculate the Bond Order of H2 (Hydrogen)**:
- H2 has a total of 2 electrons (1 from each Hydrogen).
- The molecular orbital configuration for H2 is:
\[ \sigma(1s)^2 \]
- For H2, \(N_b = 2\) and \(N_a = 0\):
\[ \text{Bond Order} = \frac{(2 - 0)}{2} = 1 \]

### Summary of Bond Orders:
- CO: Bond Order = 3
- O2: Bond Order = 2
- N2: Bond Order = 3
- H2: Bond Order = 1

### Conclusion:
The species having the same bond order as:
- CO (Bond Order = 3) is N2 (Bond Order = 3).
- O2 (Bond Order = 2) does not have a match in the given options.
- H2 (Bond Order = 1) does not have a match in the given options.

### Final Answer:
The species having bond order same as that of CO is N2.