which of the following is not the correct matches according to VESPER theory

Options

A. `ICl_2` Linear ion
B. `ICl_4^-` Square planer ion
C. `IF_5` sea -saw
D. `SO_2 ` Bent

Answer

To solve the question regarding which of the following matches is not correct according to VSEPR (Valence Shell Electron Pair Repulsion) theory, we will analyze the given options one by one, focusing on the hybridization, molecular geometry, and the presence of lone pairs.

### Step-by-Step Solution:

1. **Understanding VSEPR Theory**:
- VSEPR theory is used to predict the shape of a molecule based on the repulsion between electron pairs around a central atom. The theory states that electron pairs will arrange themselves to minimize repulsion, resulting in specific molecular geometries.

2. **Analyzing ICl2-**:
- ICl2- has a total of 3 lone pairs and 2 bonding pairs (from the two chlorine atoms).
- The hybridization of iodine in ICl2- is sp3d (5 regions of electron density).
- With 3 lone pairs occupying equatorial positions, the molecular geometry is linear.
- This match is correct according to VSEPR theory.

3. **Analyzing ICl4-**:
- ICl4- has 4 bonding pairs and 2 lone pairs.
- The hybridization of iodine in ICl4- is sp3d2 (6 regions of electron density).
- The presence of 2 lone pairs leads to a square planar geometry.
- This match is also correct according to VSEPR theory.

4. **Analyzing IF5**:
- IF5 has 5 bonding pairs and 1 lone pair.
- The hybridization of iodine in IF5 is also sp3d2 (6 regions of electron density).
- With 1 lone pair, the molecular geometry is square pyramidal.
- However, if the option states that IF5 has a different geometry (like octahedral), this would be incorrect.

5. **Conclusion**:
- Based on the analysis, the incorrect match according to VSEPR theory is related to IF5, as it does not have an octahedral geometry but rather a square pyramidal geometry.

### Final Answer:
The option that is not a correct match according to VSEPR theory is related to IF5.

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