The overlapping involved in HF molecule is

Options

A. s-s
B. s-p
C. p-p
D. s-d

Answer

To determine the type of overlapping involved in the HF (hydrogen fluoride) molecule, we can follow these steps:

### Step 1: Identify the Atoms Involved
The HF molecule consists of two atoms: hydrogen (H) and fluorine (F).

### Step 2: Determine the Electronic Configuration
- **Hydrogen (H)** has an atomic number of 1. Its electronic configuration is:
\[ 1s^1 \]
This means hydrogen has one electron in its 1s orbital.

- **Fluorine (F)** has an atomic number of 9. Its electronic configuration is:
\[ 1s^2 \, 2s^2 \, 2p^5 \]
This indicates that fluorine has two electrons in the 1s orbital, two in the 2s orbital, and five in the 2p orbital.

### Step 3: Identify the Valence Electrons
- Hydrogen has 1 valence electron in the 1s orbital.
- Fluorine has 7 valence electrons (2 in the 2s and 5 in the 2p).

### Step 4: Determine the Bonding Orbitals
To form a bond, hydrogen will use its 1s orbital, and fluorine will use one of its 2p orbitals (since it has one unpaired electron in the 2p subshell).

### Step 5: Identify the Type of Overlapping
The bond formed between hydrogen and fluorine is a covalent bond. The overlapping involved in this bond is:
- The 1s orbital of hydrogen overlaps with one of the 2p orbitals of fluorine.

### Conclusion
Thus, the overlapping involved in the HF molecule is the overlap between the 1s orbital of hydrogen and the 2p orbital of fluorine.

### Final Answer
The type of overlapping involved in the HF molecule is **s-p overlapping**.

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