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Equal weights of methane and hydrogen ar...

Equal weights of methane and hydrogen are mixed in an empty container at `25^@` C. The farction of total pressure exerted by hydrogen is

A

`1//2 `

B

8//9

C

16//19

D

1//9

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The correct Answer is:
To solve the problem of finding the fraction of total pressure exerted by hydrogen when equal weights of methane (CH₄) and hydrogen (H₂) are mixed in a container at 25°C, we can follow these steps: ### Step 1: Determine the molecular weights of methane and hydrogen - The molecular weight of methane (CH₄) is 16 g/mol. - The molecular weight of hydrogen (H₂) is 2 g/mol. ### Step 2: Assume equal weights of methane and hydrogen - Let's assume we take 1 gram of each gas. - Therefore, we have 1 g of CH₄ and 1 g of H₂. ### Step 3: Calculate the number of moles of each gas - For methane (CH₄): \[ \text{Number of moles of CH₄} = \frac{\text{Weight}}{\text{Molecular weight}} = \frac{1 \text{ g}}{16 \text{ g/mol}} = \frac{1}{16} \text{ mol} \] - For hydrogen (H₂): \[ \text{Number of moles of H₂} = \frac{\text{Weight}}{\text{Molecular weight}} = \frac{1 \text{ g}}{2 \text{ g/mol}} = \frac{1}{2} \text{ mol} \] ### Step 4: Calculate the total number of moles - Total moles = moles of CH₄ + moles of H₂ \[ \text{Total moles} = \frac{1}{16} + \frac{1}{2} \] To add these fractions, we need a common denominator: \[ \frac{1}{2} = \frac{8}{16} \] Therefore: \[ \text{Total moles} = \frac{1}{16} + \frac{8}{16} = \frac{9}{16} \text{ mol} \] ### Step 5: Calculate the mole fraction of hydrogen - The mole fraction of hydrogen (X_H₂) is given by: \[ X_{H₂} = \frac{\text{moles of H₂}}{\text{total moles}} = \frac{\frac{1}{2}}{\frac{9}{16}} \] Simplifying this: \[ X_{H₂} = \frac{1/2}{9/16} = \frac{1}{2} \times \frac{16}{9} = \frac{8}{9} \] ### Step 6: Determine the fraction of total pressure exerted by hydrogen - The fraction of total pressure exerted by hydrogen is equal to its mole fraction: \[ \text{Fraction of total pressure by H₂} = X_{H₂} = \frac{8}{9} \] ### Final Answer The fraction of total pressure exerted by hydrogen is \(\frac{8}{9}\). ---
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