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The osmotic pressure of 5% (mass/volume)...

The osmotic pressure of 5% (mass/volume) solution of cane sugar at 50 degree celsius is

A

2.51 atm

B

3 atm

C

3.88 atm

D

3.45 atm

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The correct Answer is:
To calculate the osmotic pressure of a 5% (mass/volume) solution of cane sugar (C12H22O11) at 50 degrees Celsius, we can follow these steps: ### Step 1: Understand the concentration of the solution A 5% (mass/volume) solution means that there are 5 grams of cane sugar in 100 mL of solution. ### Step 2: Convert the volume from mL to L Since osmotic pressure is typically calculated using liters, we need to convert 100 mL to liters: \[ \text{Volume (L)} = \frac{100 \text{ mL}}{1000} = 0.1 \text{ L} \] ### Step 3: Calculate the number of moles of cane sugar To find the number of moles, we use the formula: \[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] The molar mass of cane sugar (C12H22O11) is approximately 342 g/mol. Thus, the number of moles is: \[ \text{Number of moles} = \frac{5 \text{ g}}{342 \text{ g/mol}} \approx 0.0146 \text{ moles} \] ### Step 4: Calculate the concentration (C) The concentration (C) in moles per liter is given by: \[ C = \frac{\text{Number of moles}}{\text{Volume (L)}} = \frac{0.0146 \text{ moles}}{0.1 \text{ L}} = 0.146 \text{ M} \] ### Step 5: Use the osmotic pressure formula The osmotic pressure (π) can be calculated using the formula: \[ \pi = CRT \] Where: - \(C\) is the concentration in moles per liter, - \(R\) is the ideal gas constant (0.0821 L·atm/(K·mol)), - \(T\) is the temperature in Kelvin. ### Step 6: Convert the temperature to Kelvin To convert 50 degrees Celsius to Kelvin: \[ T(K) = 50 + 273 = 323 \text{ K} \] ### Step 7: Calculate the osmotic pressure Now substituting the values into the osmotic pressure formula: \[ \pi = (0.146 \text{ M}) \times (0.0821 \text{ L·atm/(K·mol)}) \times (323 \text{ K}) \] Calculating this gives: \[ \pi \approx 3.88 \text{ atm} \] ### Conclusion The osmotic pressure of the 5% (mass/volume) solution of cane sugar at 50 degrees Celsius is approximately **3.88 atm**. ---
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