Laboratory method for the preperation of diborane involves the oxidation of

Options

A. Sodium borohydride with iodine
B. Sodium borohydride with fluorine
C. Sodium borohydride with chlorine
D. Sodium borohydride with `KMnO_4`

Answer

To answer the question regarding the laboratory method for the preparation of diborane (B2H6), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**: The laboratory preparation of diborane involves the oxidation of sodium borohydride (NaBH4) using iodine (I2).

2. **Write the Chemical Equation**: The reaction can be represented as:
\[ 2 \text{NaBH}_4 + \text{I}_2 \rightarrow \text{B}_2\text{H}_6 + 2 \text{NaI} + \text{H}_2 \]
Here, sodium borohydride reacts with iodine to produce diborane, sodium iodide, and hydrogen gas.

3. **Balancing the Equation**: To ensure the equation is balanced:
- Count the number of each type of atom on both sides.
- On the left side, we have 2 sodium (Na), 2 boron (B), 8 hydrogen (H), and 2 iodine (I).
- On the right side, we have 2 sodium (Na), 2 boron (B), 6 hydrogen (H) from diborane and 2 from hydrogen gas, and 2 iodine (I) from sodium iodide.
- The equation is balanced as both sides have the same number of each type of atom.

4. **Conclusion**: The correct reagents for the laboratory preparation of diborane are sodium borohydride and iodine.

### Final Answer:
The laboratory method for the preparation of diborane involves the oxidation of sodium borohydride (NaBH4) using iodine (I2).

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