When silver chloride is treated with aqueous ammonia, the complex obtained is

Options

A. `[Ag(NH_3)_4]^oplus`
B. `[Ag(NH_3)_6]^oplus`
C. `[Ag(NH_3)_2]^oplus`
D. `[Ag(NH_3)(H_2O]^oplus`

Answer

To determine the complex formed when silver chloride (AgCl) is treated with aqueous ammonia (NH₃), we can follow these steps:

### Step 1: Understand the Reactants
- **Silver Chloride (AgCl)**: A sparingly soluble salt that dissociates into silver ions (Ag⁺) and chloride ions (Cl⁻) in solution.
- **Aqueous Ammonia (NH₃)**: A solution of ammonia in water, which can act as a ligand due to the presence of lone pairs on the nitrogen atom.

### Step 2: Reaction of AgCl with Aqueous Ammonia
- When AgCl is treated with aqueous ammonia, the silver ions (Ag⁺) interact with the ammonia molecules.
- The reaction can be represented as:
\[ \text{AgCl (s)} + 2 \text{NH}_3 (aq) \rightarrow [\text{Ag(NH}_3\text{)}_2]^+ + \text{Cl}^- \]

### Step 3: Formation of the Complex
- The complex formed is \([\text{Ag(NH}_3\text{)}_2]^+\), known as diamminesilver(I) ion.
- This complex is soluble in water, and the chloride ion (Cl⁻) is released into the solution.

### Step 4: Nature of the Complex
- The complex is reversible, meaning it can dissociate back into AgCl and ammonia under certain conditions.
- The formation of the complex is favored in the presence of excess ammonia.

### Conclusion
The complex obtained when silver chloride is treated with aqueous ammonia is \([\text{Ag(NH}_3\text{)}_2]^+\).

### Final Answer
The complex obtained is \([\text{Ag(NH}_3\text{)}_2]^+\).

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