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In vapour state, sulphur (S2) shows para...

In vapour state, sulphur `(S_2)` shows paramagnetic behaviour due to

A

Presence of one unpaired electron in the antibonding `sigma^**` orbitals

B

Presence of two unpaired electrons in the bonding pi orbitals

C

Presence of one unpaired electrons in the bonding `pi^**` orbitals

D

Presence of two unpaired electrons in the bonding `pi^**` orbitals

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The correct Answer is:
To solve the question regarding the paramagnetic behavior of sulfur in its vapor state, we need to analyze the electronic configuration of the sulfur molecule \( S_2 \) and understand the concept of paramagnetism. ### Step-by-Step Solution: 1. **Understanding the Molecular Structure of \( S_2 \)**: - Sulfur in its vapor state exists as a diatomic molecule \( S_2 \). 2. **Electronic Configuration**: - To determine the magnetic properties, we need to look at the molecular orbital (MO) theory. The molecular orbitals are formed by the combination of atomic orbitals from the two sulfur atoms. - The electronic configuration of \( S_2 \) can be derived from the atomic configuration of sulfur, which is \( [Ne] 3s^2 3p^4 \). 3. **Filling the Molecular Orbitals**: - For \( S_2 \), the molecular orbitals are filled in the order of increasing energy: - \( \sigma_{1s}^2 \) - \( \sigma_{1s}^* \) - \( \sigma_{2s}^2 \) - \( \sigma_{2s}^* \) - \( \sigma_{2p_z}^2 \) - \( \pi_{2p_x}^2 \) - \( \pi_{2p_y}^2 \) - \( \pi_{2p_x}^* \) - \( \pi_{2p_y}^* \) 4. **Identifying Unpaired Electrons**: - In the case of \( S_2 \), the two unpaired electrons are located in the \( \pi_{2p_x}^* \) and \( \pi_{2p_y}^* \) molecular orbitals. - This configuration leads to the presence of two unpaired electrons. 5. **Conclusion on Paramagnetism**: - The presence of unpaired electrons is the key factor that leads to paramagnetic behavior. Since \( S_2 \) has two unpaired electrons in the antibonding \( \pi \) orbitals, it exhibits paramagnetism in the vapor state. ### Final Answer: In vapor state, sulfur \( (S_2) \) shows paramagnetic behavior due to the presence of two unpaired electrons in the \( \pi_{2p}^* \) molecular orbitals. ---
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AAKASH INSTITUTE-MOCK TEST 25-Example
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