The number of equivalent Cr-O bonds in `CrO_4^(2-)` is

Options

A. 1
B. 2
C. 3
D. 4

Answer

To determine the number of equivalent Cr-O bonds in the chromate ion \( \text{CrO}_4^{2-} \), we can follow these steps:

### Step 1: Understand the structure of the chromate ion
The chromate ion \( \text{CrO}_4^{2-} \) consists of one chromium (Cr) atom surrounded by four oxygen (O) atoms.

### Step 2: Draw the Lewis structure
To visualize the bonding, we can draw the Lewis structure of \( \text{CrO}_4^{2-} \). In this structure:
- Chromium is the central atom.
- It forms bonds with four oxygen atoms.
- The overall charge of the ion is -2.

### Step 3: Determine the type of bonds
In the Lewis structure of \( \text{CrO}_4^{2-} \), each Cr-O bond can be represented as a single bond or a double bond depending on the resonance structures. However, due to resonance, the bonds are equivalent.

### Step 4: Count the equivalent bonds
In the case of \( \text{CrO}_4^{2-} \), all four Cr-O bonds are equivalent due to resonance. This means that each bond has the same bond length and bond character.

### Conclusion
The number of equivalent Cr-O bonds in \( \text{CrO}_4^{2-} \) is 4.

### Final Answer
The number of equivalent Cr-O bonds in \( \text{CrO}_4^{2-} \) is **4**.

---