which of the following compound will show stereo isomerism?

Options

A. 3-Pentarol
B. 3-Pentanone
C. But-2-ene
D. Propane

Answer

To determine which of the given compounds can exhibit stereoisomerism, we need to analyze each compound based on the presence of chiral centers and the ability to show geometrical isomerism.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- We have several compounds to analyze:
- A compound with no double bond and no chiral carbon.
- 3-pentanone.
- But-2-ene (butytoene).
- 4-propanone.
- 3-propanone.

2. **Analyze Each Compound**:
- **Compound with No Double Bond and No Chiral Carbon**:
- This compound cannot exhibit stereoisomerism because it lacks both chiral centers and any form of restricted rotation.

- **3-Pentanone**:
- This compound also does not have a chiral carbon and lacks a double bond that would allow for restricted rotation. Therefore, it cannot show stereoisomerism.

- **But-2-ene (Butytoene)**:
- This compound has a double bond between the second and third carbon atoms. It can exhibit geometrical isomerism (cis and trans forms) because the substituents on the double bond can be arranged differently. Thus, but-2-ene can show stereoisomerism.

- **4-Propanone**:
- Similar to the previous compounds, 4-propanone does not have a chiral carbon and does not possess a double bond that allows for restricted rotation. Therefore, it cannot exhibit stereoisomerism.

- **3-Propanone**:
- Like 4-propanone, this compound also lacks a chiral center and does not have a double bond to allow for geometrical isomerism. Hence, it cannot show stereoisomerism.

3. **Conclusion**:
- Among the compounds analyzed, only **But-2-ene (butytoene)** can exhibit stereoisomerism due to its ability to form geometrical isomers.

### Final Answer:
**But-2-ene (butytoene)** is the only compound that will show stereoisomerism.

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