The correct order of boiling points of alkyl halides is

Options

A. `CH_3FgtCH_3ClgtCH_3BrgtCH_3I`
B. `CH_3FgtCH_3BrgtCH_3ClgtCH_3I`
C. `CH_3IgtCH_3BrgtCH_3ClgtCH_3F`
D. `CH_3ClgtCH_3BrgtCH_3FgtCH_3I`

Answer

To determine the correct order of boiling points of alkyl halides, we need to consider the factors that influence boiling points, such as molecular weight and intermolecular forces.

### Step 1: Identify the Alkyl Halides
Let's consider the alkyl halides mentioned in the video:
- Methyl fluoride (CH3F)
- Methyl chloride (CH3Cl)
- Methyl bromide (CH3Br)
- Methyl iodide (CH3I)

### Step 2: Analyze Molecular Weights
Next, we will look at the molecular weights of these compounds:
- Methyl fluoride (CH3F) = 34 g/mol
- Methyl chloride (CH3Cl) = 50.5 g/mol
- Methyl bromide (CH3Br) = 94.9 g/mol
- Methyl iodide (CH3I) = 142 g/mol

### Step 3: Consider Intermolecular Forces
The boiling point is influenced by the strength of intermolecular forces. Alkyl halides primarily exhibit dipole-dipole interactions and London dispersion forces. As the size of the halogen increases, the molecular weight increases, which generally leads to stronger London dispersion forces.

### Step 4: Determine the Order of Boiling Points
Based on the molecular weights and the strength of intermolecular forces, we can arrange the alkyl halides in order of increasing boiling points:
1. Methyl fluoride (lowest boiling point)
2. Methyl chloride
3. Methyl bromide
4. Methyl iodide (highest boiling point)

### Final Order
Thus, the correct order of boiling points of the alkyl halides is:
**Methyl fluoride < Methyl chloride < Methyl bromide < Methyl iodide**