Oxidation of glucose with bromine water and nitnic acid yields respectively

Options

A. Gluconic acid and Saccharic acid
B. Saccharic acid and Gluconic acid
C. Gluconic acid and Gluconic acid
D. Saccharic acid and Saccharic acid

Answer

To solve the question regarding the oxidation of glucose with bromine water and nitric acid, we need to understand the chemical reactions that occur with these oxidizing agents.

### Step-by-Step Solution:

1. **Identify the Structure of Glucose**:
- Glucose is a simple sugar with the molecular formula C6H12O6. The structure can be represented as:
```
CH2OH
|
HO-CH
|
HO-CH
|
HO-CH
|
CHO
```
- In this structure, the terminal -CH2OH group is a primary alcohol, and the -CHO group is an aldehyde.

2. **Oxidation with Bromine Water**:
- Bromine water (Br2 in water) is a mild oxidizing agent. It primarily oxidizes the primary alcohol group (-CH2OH) of glucose to an aldehyde (-CHO).
- The oxidation of the primary alcohol results in the formation of gluconic acid (C6H12O7), which is an aldonic acid. The structure of gluconic acid can be represented as:
```
CHO
|
HO-CH
|
HO-CH
|
HO-CH
|
COOH
```

3. **Oxidation with Nitric Acid**:
- Nitric acid (HNO3) is a strong oxidizing agent. It can oxidize both the aldehyde group and the primary alcohol group.
- The aldehyde (-CHO) group is oxidized to a carboxylic acid (-COOH), and the primary alcohol (-CH2OH) is also oxidized to a carboxylic acid.
- The final product of this oxidation is saccharic acid (C6H10O8), which has two carboxylic acid groups. The structure of saccharic acid can be represented as:
```
COOH
|
HO-CH
|
HO-CH
|
HO-CH
|
COOH
```

4. **Conclusion**:
- Therefore, the oxidation of glucose with bromine water yields gluconic acid, and the oxidation with nitric acid yields saccharic acid.

### Final Answer:
The oxidation of glucose with bromine water and nitric acid yields respectively gluconic acid and saccharic acid.