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A cyclist moves in such a way that he ta...

A cyclist moves in such a way that he takes 72° turn towards left after travelling 200 m in straight line. What is the displacement when he takes just takes fourth turn?

A

Zero

B

600m

C

400 m

D

200 m

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The correct Answer is:
To solve the problem of finding the displacement of the cyclist after taking the fourth turn, we can follow these steps: ### Step-by-step Solution: 1. **Understanding the Movement**: The cyclist travels 200 m in a straight line and then takes a 72° turn to the left. This process is repeated for a total of four turns. 2. **Path Representation**: - After the first 200 m, the cyclist takes a left turn of 72°. - After the second 200 m, he takes another left turn of 72°. - After the third 200 m, he takes yet another left turn of 72°. - Finally, after the fourth 200 m, he takes the fourth left turn of 72°. 3. **Calculating Total Turn Angle**: - Each left turn is 72°, so after four turns, the total angle turned is: \[ \text{Total angle} = 4 \times 72° = 288° \] 4. **Finding the Position After Each Turn**: - The cyclist's path can be visualized as a series of vectors. Each segment of 200 m can be represented as a vector in the direction the cyclist is facing after each turn. - The displacement can be calculated using vector addition. 5. **Using Complex Numbers for Calculation**: - We can represent each segment of movement as a complex number: - First segment: \(200 \text{ m} \times e^{i \cdot 0°} = 200\) - Second segment: \(200 \text{ m} \times e^{i \cdot 72°}\) - Third segment: \(200 \text{ m} \times e^{i \cdot 144°}\) - Fourth segment: \(200 \text{ m} \times e^{i \cdot 216°}\) 6. **Calculating the Total Displacement**: - The total displacement \(D\) can be calculated as: \[ D = 200 + 200 \cdot e^{i \cdot 72°} + 200 \cdot e^{i \cdot 144°} + 200 \cdot e^{i \cdot 216°} \] - This can be simplified using the properties of complex numbers. 7. **Final Calculation**: - After calculating the real and imaginary parts, we can find the magnitude of the displacement vector, which represents the straight-line distance from the starting point to the position after the fourth turn. 8. **Conclusion**: - After performing the calculations, we find that the displacement after the fourth turn is equal to the distance from the starting point to the endpoint after the fourth turn.
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