A particle moves on a straight line with velocity 2 m/s covers a distance of 5 m, returns back to initial position along same path with velocity 4 m/s. The distance and displacement covered by particle are respectively.

Options

A. 10 m, zero
B. Zero, 10 m
C. 5 m, 5 m
D. Zero, zero

Answer

To solve the problem step by step, we need to analyze the motion of the particle based on the information provided.

### Step 1: Understand the Motion
The particle first moves in one direction and then returns to its starting point. It covers a distance of 5 meters in the first part of the motion and then returns back to the initial position.

### Step 2: Calculate the Total Distance Covered
- The particle moves 5 meters away from the starting point.
- Then, it returns back to the starting point, covering another 5 meters.

Total distance covered = Distance going + Distance returning
\[ \text{Total Distance} = 5 \, \text{m} + 5 \, \text{m} = 10 \, \text{m} \]

### Step 3: Calculate the Displacement
Displacement is defined as the change in position from the initial point to the final point. Since the particle returns to its starting position:
- Initial position = 0 m
- Final position = 0 m

Displacement = Final position - Initial position
\[ \text{Displacement} = 0 \, \text{m} - 0 \, \text{m} = 0 \, \text{m} \]

### Final Results
- Total distance covered by the particle = 10 m
- Displacement = 0 m

### Summary
The distance and displacement covered by the particle are respectively:
- Distance = 10 m
- Displacement = 0 m