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The ratio of average spreed to the rms s...

The ratio of average spreed to the rms spreed of the gas is

A

`sqrt8:sqrt3pi`

B

`sqrt3pi:sqrt8`

C

`sqrt6:sqrt5pi`

D

`sqrt8:sqrt5pi`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of average speed to the RMS speed of a gas, we can follow these steps: ### Step 1: Write the formula for average speed The average speed (\(V_{avg}\)) of gas molecules is given by the formula: \[ V_{avg} = \sqrt{\frac{8RT}{\pi m}} \] where: - \(R\) is the gas constant, - \(T\) is the absolute temperature in Kelvin, - \(m\) is the molar mass of the gas. ### Step 2: Write the formula for RMS speed The root mean square (RMS) speed (\(V_{rms}\)) of gas molecules is given by the formula: \[ V_{rms} = \sqrt{\frac{3RT}{m}} \] ### Step 3: Set up the ratio of average speed to RMS speed We need to find the ratio of average speed to RMS speed: \[ \frac{V_{avg}}{V_{rms}} = \frac{\sqrt{\frac{8RT}{\pi m}}}{\sqrt{\frac{3RT}{m}}} \] ### Step 4: Simplify the ratio To simplify the ratio, we can rewrite it as: \[ \frac{V_{avg}}{V_{rms}} = \frac{\sqrt{\frac{8RT}{\pi m}}}{\sqrt{\frac{3RT}{m}}} = \frac{\sqrt{8RT}}{\sqrt{3RT}} \cdot \frac{1}{\sqrt{\pi}} \cdot \sqrt{m} \] The \(RT\) terms cancel out: \[ = \frac{\sqrt{8}}{\sqrt{3}} \cdot \frac{1}{\sqrt{\pi}} = \frac{\sqrt{8}}{\sqrt{3\pi}} \] ### Step 5: Final expression Thus, the ratio of average speed to RMS speed is: \[ \frac{V_{avg}}{V_{rms}} = \sqrt{\frac{8}{3\pi}} \] ### Conclusion The final answer is: \[ \frac{V_{avg}}{V_{rms}} = \sqrt{\frac{8}{3\pi}} \] ---
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