If an object contains `n_1`, protons and `n_2` electrons the net charge on the object is

Options

A. `(n_1+n_2)e`
B. `(n_1-n_2)e`
C. `(n_2-n_1)e`
D. Zero

Answer

To find the net charge on an object that contains \( n_1 \) protons and \( n_2 \) electrons, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Charges of Protons and Electrons**:
- Protons have a positive charge, denoted as \( +e \).
- Electrons have a negative charge, denoted as \( -e \).

2. **Calculate the Total Charge from Protons**:
- If there are \( n_1 \) protons, the total charge contributed by the protons is:
\[ \text{Charge from protons} = n_1 \times (+e) = n_1 e \]

3. **Calculate the Total Charge from Electrons**:
- If there are \( n_2 \) electrons, the total charge contributed by the electrons is:
\[ \text{Charge from electrons} = n_2 \times (-e) = -n_2 e \]

4. **Determine the Net Charge**:
- The net charge \( Q \) on the object is the sum of the charges from protons and electrons:
\[ Q = \text{Charge from protons} + \text{Charge from electrons} \]
Substituting the values we calculated:
\[ Q = n_1 e + (-n_2 e) = n_1 e - n_2 e \]
This simplifies to:
\[ Q = (n_1 - n_2) e \]

5. **Conclusion**:
- The net charge on the object is given by:
\[ Q = (n_1 - n_2) e \]

### Final Answer:
The net charge on the object is \( (n_1 - n_2)e \).

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