If `10^18` electrons are taken out every second from a body, then how much time is required to get a total charge of 0.1 C from it?

Options

A. 0.625s
B. 6.25s
C. 62.5s
D. 625s

Answer

To solve the problem, we need to determine how much time is required to extract a total charge of 0.1 Coulombs from a body when `10^18` electrons are taken out every second.

### Step-by-Step Solution:

1. **Identify the charge of one electron**:
The charge of a single electron is approximately \( 1.6 \times 10^{-19} \) Coulombs.

2. **Calculate the total charge extracted per second**:
If \( 10^{18} \) electrons are taken out every second, the total charge extracted in one second can be calculated as:
\[ \text{Charge per second} = \text{Number of electrons} \times \text{Charge of one electron} \]
\[ \text{Charge per second} = 10^{18} \times 1.6 \times 10^{-19} = 0.16 \text{ Coulombs} \]

3. **Set up the relationship for total charge**:
Let \( t \) be the time in seconds required to extract a total charge of 0.1 Coulombs. The relationship can be expressed as:
\[ \text{Total charge} = \text{Charge per second} \times t \]
\[ 0.1 = 0.16 \times t \]

4. **Solve for time \( t \)**:
Rearranging the equation gives:
\[ t = \frac{0.1}{0.16} \]
Calculating this value:
\[ t = 0.625 \text{ seconds} \]

5. **Conclusion**:
Therefore, the time required to extract a total charge of 0.1 Coulombs from the body is \( 0.625 \) seconds.