Two copper pieces, each of mass 0.0635 kg are placed at a distance of 0.1 m from each other One electron from each atom of piece 1 is transferred to piece 2 of copper. Net charges on piece 1 and piece 2 after transfer of electrons respectively will be

Options

A. `q_1=-1.6 x 10^(-19) C,q_2= +1.6 x 10^(-19)C`
B. `q_1=-9.6 x 10^(4) C,q_2= +9.6 x 10^(4)C`
C. `q_1=+1.6 x 10^(-19) C,q_2= -1.6 x 10^(-19)C`
D. `q_1=+9.6 x 10^(4) C,q_2= -9.6 x 10^(4)C`

Answer

To solve the problem, we need to determine the net charges on two copper pieces after transferring one electron from each atom of piece 1 to piece 2.

### Step-by-Step Solution:

1. **Identify the mass of each copper piece:**
- Given mass of each copper piece = 0.0635 kg.
- Convert this mass into grams:
\[ 0.0635 \, \text{kg} = 63.5 \, \text{grams} \]

2. **Calculate the number of moles of copper in each piece:**
- The molar mass of copper (Cu) = 63.5 g/mol.
- Number of moles of copper in each piece:
\[ \text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{63.5 \, \text{g}}{63.5 \, \text{g/mol}} = 1 \, \text{mole} \]

3. **Calculate the number of atoms in each piece:**
- Using Avogadro's number (\(6.02 \times 10^{23}\) atoms/mole):
\[ \text{Number of atoms} = \text{Number of moles} \times \text{Avogadro's number} = 1 \, \text{mole} \times 6.02 \times 10^{23} \, \text{atoms/mole} = 6.02 \times 10^{23} \, \text{atoms} \]

4. **Determine the charge of the electrons transferred:**
- Each electron has a charge of \(1.6 \times 10^{-19}\) Coulombs.
- Since one electron is transferred from each atom of piece 1 to piece 2, the total number of electrons transferred = number of atoms = \(6.02 \times 10^{23}\).
- Total charge transferred from piece 1 to piece 2:
\[ \text{Total charge} = \text{Number of electrons} \times \text{Charge of one electron} = 6.02 \times 10^{23} \times (-1.6 \times 10^{-19}) \, \text{C} \]
\[ = -9.632 \times 10^{4} \, \text{C} \]

5. **Calculate the net charge on each piece after the transfer:**
- **For Piece 1:**
- Initially, Piece 1 is neutral (0 C). After losing electrons, it will have a positive charge:
\[ Q_1 = +9.632 \times 10^{4} \, \text{C} \]
- **For Piece 2:**
- Initially, Piece 2 is also neutral (0 C). After gaining electrons, it will have a negative charge:
\[ Q_2 = -9.632 \times 10^{4} \, \text{C} \]

### Final Answer:
- Net charge on Piece 1: \(+9.632 \times 10^{4} \, \text{C}\)
- Net charge on Piece 2: \(-9.632 \times 10^{4} \, \text{C}\)