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Two point charges +10 muC and +20 muC re...

Two point charges +10 muC and +20 muC repel each other with a force of 100N. If a charge of-2 muC is added to each charge, then force between them will become

A

72N

B

7.2N

C

720N

D

100N

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The correct Answer is:
To solve the problem, we will use Coulomb's law, which states that the force \( F \) between two point charges is given by the formula: \[ F = k \frac{|Q_1 Q_2|}{d^2} \] where: - \( F \) is the force between the charges, - \( k \) is Coulomb's constant (\( k \approx 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \)), - \( Q_1 \) and \( Q_2 \) are the magnitudes of the charges, - \( d \) is the distance between the charges. ### Step 1: Identify the initial charges and force The initial charges are: - \( Q_1 = +10 \, \mu C = 10 \times 10^{-6} \, C \) - \( Q_2 = +20 \, \mu C = 20 \times 10^{-6} \, C \) The initial force between them is given as: - \( F = 100 \, N \) ### Step 2: Write the equation for the initial force Using Coulomb's law, we can express the initial force as: \[ 100 = k \frac{|10 \times 10^{-6} \cdot 20 \times 10^{-6}|}{d^2} \] ### Step 3: Calculate the new charges after adding -2 µC Now, we add -2 µC to each charge: - New \( Q_1' = 10 \, \mu C - 2 \, \mu C = 8 \, \mu C = 8 \times 10^{-6} \, C \) - New \( Q_2' = 20 \, \mu C - 2 \, \mu C = 18 \, \mu C = 18 \times 10^{-6} \, C \) ### Step 4: Write the equation for the new force The new force \( F' \) can be expressed as: \[ F' = k \frac{|Q_1' Q_2'|}{d^2} = k \frac{|8 \times 10^{-6} \cdot 18 \times 10^{-6}|}{d^2} \] ### Step 5: Relate the new force to the initial force We can relate the new force to the initial force using the ratio of the charges: \[ F' = F \cdot \frac{Q_1' Q_2'}{Q_1 Q_2} \] Substituting the values: \[ F' = 100 \cdot \frac{(8 \times 10^{-6})(18 \times 10^{-6})}{(10 \times 10^{-6})(20 \times 10^{-6})} \] ### Step 6: Simplify the expression Calculating the ratio: \[ F' = 100 \cdot \frac{(8 \cdot 18)}{(10 \cdot 20)} = 100 \cdot \frac{144}{200} = 100 \cdot 0.72 = 72 \, N \] ### Final Answer Thus, the new force between the charges after adding -2 µC to each is: \[ F' = 72 \, N \]
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