Home
Class 12
PHYSICS
Two sources of equal emf are connected t...

Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are `R_1 and R_2(R_1gtR_1).` if the potential difference across the source having internal resistance `R_2` is zero, then

A

`1 Omega`

B

`2/3 Omega`

C

`2 Omega`

D

`6 Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 9

    AAKASH INSTITUTE|Exercise Example|13 Videos

  • MOCK_TEST_17

    AAKASH INSTITUTE|Exercise Example|15 Videos

Similar Questions

Explore conceptually related problems

Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R_(1) and R_(2) (R_(1) gt R_(1)) . If the potential difference across the source having internal resistance R_(2) is zero, then

Internal resistance of battery of emf 2E is R_1 and battery of emf E is R_2 . If the potential difference across the cell of emf 2E is zero, then value of R is

Two cells, having the same emf, are connected in series through an external resistance R . Cells have internal resistance r_(1) and r_(2) (r_(1) gt r_(2)) respectively. When the circuit is closed, the potentail difference across the first cell is zero the value of R is

Two sources of current of equal emf are connected in series and having different internal resistance r_1 and r_2(r_2gtr_1) . Find the external resistance R at which the potential difference across the terminals of one of the sources becomes equal to zero.

If E is the emf of a cell of internal resistance r and external resistance R, then potential difference across R is given as

Cell having an emf epsilon internal resistance r is connected a variable external resistance R As the resistance R is increased the piot of potential difference V across R is given by