Home
Class 12
PHYSICS
Two coils are having magnetic field B an...

Two coils are having magnetic field B and 2B at their centres and current i and 2i then the ratio of their radius is

A

`1:2`

B

`2:1`

C

`1:1`

D

`4:1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the magnetic fields produced by the two coils and relate them to their respective currents and radii. ### Step-by-Step Solution: 1. **Understanding Magnetic Field in a Coil:** The magnetic field \( B \) at the center of a circular coil carrying current \( i \) is given by the formula: \[ B = \frac{\mu_0 i}{2R} \] where \( \mu_0 \) is the permeability of free space and \( R \) is the radius of the coil. 2. **Setting Up the Given Information:** - For the first coil, the magnetic field is \( B \) and the current is \( i \). - For the second coil, the magnetic field is \( 2B \) and the current is \( 2i \). 3. **Applying the Formula for Both Coils:** - For the first coil: \[ B = \frac{\mu_0 i}{2R_1} \] - For the second coil: \[ 2B = \frac{\mu_0 (2i)}{2R_2} \] 4. **Simplifying the Second Coil's Equation:** From the second coil's equation, we can simplify: \[ 2B = \frac{\mu_0 (2i)}{2R_2} \implies 2B = \frac{\mu_0 i}{R_2} \] 5. **Relating the Two Magnetic Fields:** Now we have two equations: - \( B = \frac{\mu_0 i}{2R_1} \) - \( 2B = \frac{\mu_0 i}{R_2} \) 6. **Expressing \( R_1 \) and \( R_2 \):** From the first equation, we can express \( R_1 \): \[ R_1 = \frac{\mu_0 i}{2B} \] From the second equation, we can express \( R_2 \): \[ R_2 = \frac{\mu_0 i}{2B} \] 7. **Finding the Ratio of Radii:** Now, we find the ratio \( \frac{R_1}{R_2} \): \[ \frac{R_1}{R_2} = \frac{\frac{\mu_0 i}{2B}}{\frac{\mu_0 i}{2(2B)}} = \frac{1}{1} \] 8. **Conclusion:** Therefore, the ratio of the radii \( R_1 : R_2 \) is: \[ R_1 : R_2 = 1 : 1 \] ### Final Answer: The ratio of their radii is \( 1 : 1 \).
Promotional Banner

Topper's Solved these Questions

  • Mock Test 28

    AAKASH INSTITUTE|Exercise EXAMPLE|25 Videos
  • Mock Test 31: PHYSICS

    AAKASH INSTITUTE|Exercise Example|23 Videos

Similar Questions

Explore conceptually related problems

The magnetic field at the centre of current carrying coil is

The magnetic field at the centre of the current carrying coil

Calculate the change in magnetic field induction at the centre of a current carrying loop of radius R, if the radius of coil is reduced to half and current through it changes from I to 2I .

Ratio of magnetic field at the centre of a current carrying coil of radius R and at a distance of 3R on its axis is

When equal current is passed through two coils equal magnetic field is produced at their centres. If the ratio of number of turns in the coils is 8:15 then the ratio of the their radii will be

A circular coil of 100 turns has a radius of 10 cm and carries a current of 5A. Calculate the magnetic field (a) at the centre of the coil (b) at a point on the axis of the coil at a distanceof 5cm from the centre of the coil.

The ratio of the magnetic field at the centre of a current carrying circular wire and the magnetic field at the centre of a semi-circular coil made from the same length of wire will be

The ratio of the magnetic field at the centre of a current carrying circular wire and the magnetic field at the centre of a square coil made from the same length of wire will be

Current I A flowing in a circular coil of radius r. then the magnetic induction at the centre is B. If the current is doubled then the magnetic induction will be

The ratio of the magnetic field at the centre of a current carrying coil of the radius a and at distance 'a' from centre of the coil and perpendicular to the axis of coil is