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The voltage over a cycle varies as V=V...

The voltage over a cycle varies as
`V=V_(0)sin omega t` for `0 le t le (pi)/(omega)`
`=-V_(0)sin omega t` for `(pi)/(omega)le t le (2pi)/(omega)`
The average value of the voltage one cycle is

A

`V_0/sqrt2`

B

`2V_0 /pi`

C

`V_0/ pi`

D

`sqrt2V_0 / pi`

Text Solution

Verified by Experts

The correct Answer is:
B
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