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Sum of the areas of two squares is 544 m...

Sum of the areas of two squares is `544 m^(2)`. If the difference of their perimeters is 32 m. find the sides of two squares.

A

[AT]

B

`[A]`

C

`[ML²T^-2]`

D

`[ML^-1T^-2]`

Text Solution

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The correct Answer is:
B
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AAKASH INSTITUTE-Mock Test 34: PHYSICS-Example
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