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de Broglie wavelength of an electron aft...

de Broglie wavelength of an electron after being accelerated by a potential difference of V volt from rest is :

A

`lambda=12.27/√v cm`

B

`lambda=12.27/√v mm`

C

`lambda=12.27/√v cm`

D

`lambda=12.27/√v A`

Text Solution

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The correct Answer is:
D
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