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What percentage (approximate) of origina...

What percentage (approximate) of original radioactive substance left after 4 half-Life?

A

0.08

B

0.06

C

0.04

D

0.03

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The correct Answer is:
To determine the percentage of the original radioactive substance left after 4 half-lives, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Half-Life**: The half-life of a radioactive substance is the time required for half of the substance to decay. 2. **Initial Amount**: Let's denote the initial amount of the radioactive substance as \( A \). 3. **After 1 Half-Life**: After one half-life, the amount remaining is: \[ \text{Remaining after 1 half-life} = \frac{A}{2} \] 4. **After 2 Half-Lives**: After two half-lives, the amount remaining is: \[ \text{Remaining after 2 half-lives} = \frac{A}{2^2} = \frac{A}{4} \] 5. **After 3 Half-Lives**: After three half-lives, the amount remaining is: \[ \text{Remaining after 3 half-lives} = \frac{A}{2^3} = \frac{A}{8} \] 6. **After 4 Half-Lives**: After four half-lives, the amount remaining is: \[ \text{Remaining after 4 half-lives} = \frac{A}{2^4} = \frac{A}{16} \] 7. **Calculating the Percentage Left**: To find the percentage of the original substance that remains, we use the formula: \[ \text{Percentage remaining} = \left( \frac{\text{Remaining amount}}{\text{Original amount}} \right) \times 100 \] Substituting the values we have: \[ \text{Percentage remaining} = \left( \frac{\frac{A}{16}}{A} \right) \times 100 = \frac{1}{16} \times 100 \] 8. **Final Calculation**: \[ \text{Percentage remaining} = \frac{100}{16} = 6.25\% \] ### Conclusion: After 4 half-lives, approximately **6.25%** of the original radioactive substance remains.
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