ABC is a triangle and the internal angle bisector of angle A cuts the side BC at D. If A=(3,-5), B(-3,3), C=(-1,-2) then find the length AD

In Delta ABC , internal angle bisector of angle A meets side BC in D. DE bot AD meets AC in E and AB in F. Then

In a Delta ABC, I is the incentre and AI cuts BC at D. If B=(-1,2) C(9,7), AB = 14, AC =21 then find D.

In a triangle ABC, if A-=(1,2) and the internal angle bisectors through B and C are y=x and y=-2x, then the inradius r of DeltaABC is

If two shorter sides of a triangle measure 9 and 18. If the internal angle bisector drawn to the longest side is 8 then length of longest side of the triangle.

If the bisector angle A of the triangle ABC makes an angle theta with BC, then sin theta=

In DeltaABC with fixed length of BC , the internal bisector of angle C meets the side AB at D and the circumcircle at E . The maximum value of CD xx DE is

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the internal angle bisector of angleABC is x+y =2 Equation of BC is