Home
Class 12
PHYSICS
A cube of side 20 cm is kept in a region...

A cube of side 20 cm is kept in a region as shown in the figure. An electric field `vecE` exists in the region such that the potential at a point is given by `V=10x+5`, where V is in volt and x is in m.

Find the
(i) electric field `vecE`, and
(ii) total electric flux through the cube.

Text Solution

Verified by Experts

(i) Here potential `V=10x+5`
`therefore ` Electric field `vecE= -(dV)/(dr)= -(delV)/(del x) hati-(delV)/(del y) hatj-(delV)/(del z)hatk=-10hatiVm^(-1)`
(ii) As `vecE` is directed along x-axis and is constant at all points, so we shall have flux associated with two opposite faces of cube in y-z plane. However, flux with each of the two faces is equal but at one face it is outgoing and at the other it is incoming one. Hence, net flux `phi_(B)=0`.
Promotional Banner

Topper's Solved these Questions

  • CBSE EXAMINATION PAPER 2020

    U-LIKE SERIES|Exercise SECTION C|10 Videos

  • ATOMS

    U-LIKE SERIES|Exercise SELF ASSESSMENT TEST (SECTION C)|2 Videos

  • CBSE EXAMINATION PAPER 2020 (SOLVED)

    U-LIKE SERIES|Exercise SECTION D|11 Videos

Similar Questions

Explore conceptually related problems

Let V_0 be the potential at the origin in an electric field vecE = 4hati + 5hatj . The potential at the point (x,y) is

Electric potential at any point in a region is given as V=5x+3y+sqrt15z In this region the magnitude of the electric field is:

A cube of edge a is kept on x-axis in a region where electric field varies with distance as E = kx hati . Total electric flux associated with the cube is-

Find the electric field in region II as in figure shown.

Find the electric field in region II as shown in figure.

The electirc potential at a point (x, y, z) is given by V = -x^(2)y - xz^(3) + 4 The electric field vecE at that point is

Let V_(0) be the potential at the origin in an electric field vecE=E_(x)hati+E_(y)hatj . The potential at the point (x,y) is