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Suppose that alpha-beta is not an odd mu...

Suppose that `alpha-beta` is not an odd multiple of `(pi)/2, m in R-{0,-1}` an `(sin (alpha+beta))/(cos(alpha-beta))=(1-m)/(1+m)`. Then show that `tan((pi)/4-alpha)=mtan((pi)/4+beta)`

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The correct Answer is:
`((pi)/4+beta)`
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