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cos20^(@)cos40^(@)-sin5^(@)sin25^(@)=...

`cos20^(@)cos40^(@)-sin5^(@)sin25^(@)=`

A

0

B

`(sqrt(3)+1)/4`

C

`(sqrt(3)-1)/2`

D

`(sqrt(3)-1)/4`

Text Solution

Verified by Experts

The correct Answer is:
B
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Prove that cos 20^(@) cos 40^(@) - sin5^(@) sin 25^(@) = (sqrt(3)+1)/(4) .

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Knowledge Check

  • cos20^(@)cos40^(@)cos60^(@)cos80^(@)=

    A
    `1//2`
    B
    `1//4`
    C
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    D
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  • (cos20^(@)+8sin10^(@)sin50^(@)sin70^(@))/(sin^(2)80^(@))=

    A
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    B
    2
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    D
    4

  • cos70^(@)+sin40^(@)=

    A
    `sin10^(@)`
    B
    `cos10^(@)`
    C
    `tan10^(@)`
    D
    `cot 10^(@)`

    • Similar Questions

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    Find the values of the following : Tan((pi)/(4)+theta).Tan((pi)/(4)-theta) Sin1140^(@).cos40^(@)-cos780^(@).sin750^(@)

    Prove that (sin70^(@)-cos40^(@))/(cos50^(@)-sin20^(@)) = 1/(sqrt(3)) .

    Simplify cos 100^(@) cos 40^(@) +sin 100^(@) sin 40^(@)

    S.T cos340^(@) . Cos40^(@)+sin200^(@).sin140^(@)=(1)/(2)

    Show that cos 340^(@) cos 40^(@)+sin 200^(@) sin 140^(@) = 1/2 .

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