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If cos theta =(a cos phi+b)/(a+bcosphi) ...

If `cos theta =(a cos phi+b)/(a+bcosphi)` then `("tan"(theta)/2)/("tan"(phi)/2)=`

A

`(a-b)/(a+b)`

B

`(a+b)/(a-b)`

C

`sqrt((a+b)/(a-b))`

D

`sqrt((a-b)/(a+b))`

Text Solution

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The correct Answer is:
D
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