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In DeltaABC, (sin2A+sin2B+sin 2C)/(sinA+...

In `DeltaABC, (sin2A+sin2B+sin 2C)/(sinA+sinB+sinC)=`

A

`4sin A//2sin B//2sinC//2`

B

`4cos A//2 cos B//2 cos C//2`

C

`8 sin A//2 sinB//2 sin C//2`

D

`1+4sin A//2 sin B//2 sin C//2`

Text Solution

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The correct Answer is:
C
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