Home
Class 12
MATHS
Equation of plane through (1,0,2) and li...

Equation of plane through (1,0,2) and line of intersection of planes `vecr*(hati+hatj+hatk)=1` and `vecr*(hati-2hatj)=-2`

A

`vecr*(hati+7hatj+3hatk)=7`

B

`vecr*(3hati+10hatj+3hatk)=7`

C

`vecr*(hati+hatj-3hatk)=4`

D

`vecr*(hati+4hatj-hatk)=-7`

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the plane through the line of intersection of the planes vecr.(2hati-3hatj+4hatk)=1 and vecr.(hati-hatj)+4=0 and perpendicular to the plane vecr.(2hati-hatj+hatk)+8=0 .

Find the equation of the plane passing through the line of intersection of the planes vecr.(hati+hatj+hatk)=1 and vecr.(2hati+3hatj-hatk)+4=0 and parallel to x-axis.

The line of intersection of the planes vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2 is:

Equation of a plane passing through the intersection of the planes vecr.(3hati-hatj+hatk)=1 and vecr.(hati+4hatj-2hatk)=2 and passing through the point (hati+2hatj-hatk) is :

The vector equation of the pane passing through the intersection of the planes vecr.(hati+hatj+hatk)=1 and vecr.(hati-2hatj)=-2 and the point (1,0,2) is

Prove that the equaton of a plane through point (2,-4,5) and the line o lintersection of the planes vecr.(2hati+3hatj-hatk) = 1 and vecr.(3hati+hatj-2hatk) = 2 is vecr.(2hati+8hatj+7hatk) = 7 .

Find the equation of the plane passing through the line of intersection of the planes vecr.(hati+3hatj)-6=0 and vecr.(3hati-hatj-4hatk)=0 , whose perpendicular distance from the origin is unity.

Find the Cartesian and vector equation of the planes through the line of intersection of the planes vecr.(hati-hatj)+6=0 and vecr.(3hati+3hatj-4hatk)=0 , which are at a unit distance from the origin.

If the equation of the plane through the line of interesection of vecr.(2hati-3hatj+hatk)=1 and vecr.(hati-hatj)+4=0 and perpendicular to vecr.(2hati+hatj+hatk)+8=0 is vecr.(5hati-2hatj-12hatk)=lamda Then lamda=