For the following combustion reaction
`C_xH_y + mO_2 to nCO_2 +pH_2O`
oxygen required 6 times the volume of hydrocarbon and `CO_2` produces is 4 times the volume of hydrocarbon. what will be the value of y.

In the complete combustion of hydrocarbon (C_(n)H_(2n+2)) the number of oxygen molecules required per mole of hydrocarbon is

What is the volume of a cuboid of dimensions 2.8 cm times 1.6 cm times 4 cm?

10 mL of a certain hydrocarbon require 25 mL of oxygen for complete combustion and the volume CO_(2) of product is 20 mL. What is the formula of hydrocarbon ?

A hydrocarbon is burnt with just sufficient amount of oxygen. After combustion the volume contraction was 2.5 times of volume of hydrocarbon burnt. On passing this mixture through KOH, if volume contraction is twice the volume of hydrocarbon taken. Calculate no. of atoms in one molecule of the hydrocarbon.

The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O_2 for complete oxidation and produces 4 time its own volume of CO_2 is C_(x)H_(y) . The value of y is _________

When a gaseous olefinic hydrocarbon is burnt completely in excess of O_(2) , a contraction in volume equal to double to the volume of hydrocarbon is noticed then hydrocarbon will be

1 mole of hydrocarbon on complete combustion give 4 mole of CO_(2) . Calculate no of carbon in hydrocarbon.

When one of the following hydrocarbon is burnt in excess of oxygen, the volume of CO_(2) evolved is just three times to that of hydrocarbon taken. The hydrocarbon is