For a reaction value of rate constant becomes 5 tomes when temp. is increased from `27^@C` to `52^@C`. Find the activation energy?

The rate constant is doubled when temperature increases from 27^(@)C to 37^(@)C . Activation energy in kJ is

The specific rate constant for a reaction increases by a factor of 4, if the temperature is changed from 27^(@)C" to "47^(@)C . Find the activation energy for the reaction.

If the rate of a reaction gets doubled as the temperature is increased from 27^@ " to " 37^@C . Find the activation energy of reaction?

A particular reaction rate increases by a a factor of five when the temperature is increased from 5^(@) to 27^(@) C. What is the activation energy of the reaction?

The specific rate constant of a particular reaction quadruples when temperature is changed from 27^@" to "47^@C . Find activation energy for the reaction.

The rate constant for a first order reaction becomes six times when the temperature is raised from 350 K to 400 K. Calculate the activation energy for the reaction [R=8.314JK^(-1)mol^(-1)]

The rate constant of a reaction increases by 5% when its temperature is raised from 27^@c to 28^@c. The activation energy of the reaction is

The rate constant of a reaction increases by five times on increase in temperature from 27^@C to 52^@C . The value of activation energy in kJ "mol"^(-1) is ______ (Rounded-off to the nearest integer)

The rate of a reaction becomes 4 times when temperature is raised from 293 K to 313 K. The activation energy for such reaction would be