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MAXIMUM PUBLICATION-INVERSE TRIGNOMETRY-EXAMPLE
- Solve 2tan^-1(cosx)=tan^-1(2cosx)
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- Prove that sin^-1frac12(13)+cos^-1frac4(5)+tan^-1frac63(16)=pi
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- Find the principal value of sec^-1(-frac(2)(sqrt3))
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- If sin(sin^-1(frac(1)(5))+cos^-1(x))=1
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- Solve the following tan^-1(frac(1-x)(1+x))=1/2tan^-1x
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- Solve the following sin^-1x+sin^-1 2x=pi/3
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- Choose the correct answer from the bracket. cos(tan^-1x),|x|<1 is ...
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- Prove that sin^-1frac(4)(5)+sin^-1frac(5)(13)=sin^-1frac(63)(65)
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- In which quadrants are the graph of cos^-1(x) lies,x in [-1,1]
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- If cos^-1x+cos^-1y=pi/3,then sin^-1x+sin^-1y=………..
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- if tan^-1x+tan^-1y=pi/4 then prove that x+y+xy=1
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- sin(tan^-1(1)) is equal to
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- if x in(o,pi/2),show that cot^-1(frac(sqrt(1+sinx)+sqrt(1-sinx))(sqr...
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- show that sin^-1frac(3)(5)-sin^-1frac(8)(17)=cos^-1frac(84)(85)
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- Choose the correct answer from the bracket. if cos^-1x=y,then y is...
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- find the value of cos^-1cos((7pi)/3)
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- Solve for x if,tan^-1(frac(1+x)(1-x))=2tan^-1x
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- Find the principal value of cos^-1(frac(sqrt3)(2))
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- Prove that 2 sin^-1(frac(3)(5))=tan^-1(frac(24)(7))
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- Prove 2tan^-1frac(1)(2)+tan^-1frac(1)(7)=tan^-1frac(31)(17)
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