Let x and y be the length and breadth of the rectangle ABCD in a circle having radius r. Let `angleCAB=theta` (Ref. Figure). If `triangle` represent area of the rectangle and r is a constant.
Write `triangle` in terms of r and `theta`.

Let x and y be the length and bredth of the rectangle ABCD in a circle having radius r. Let angleCAB=theta (Ref. Figure). If triangle represent area of the rectangle and r is a constant. Hence find the maximum value of triangle .

Let x and y be the length and breadth of the rectangle ABCD in a circle having radius r. Let angleCAB=theta (Ref. Figure). If triangle represent area of the rectangle and r is a constant. Find (d triangle)/(d theta) and (d^2 triangle)/(d theta^2) .

Let x and y be the length and bredth of the rectangle ABCD in a circle having radius r. Let angleCAB=theta (Ref. Figure). If triangle represent area of the rectangle and r is a constant. Show that the rectangle of maximum area that can be inscribed in a circle of radius r is a square of side sqrt2r .

Let ABCbe an isosceles triangle inscribed ina circle having radius r. Then by figure area of the triangle ABC is triangle Find (d triangle)/(d theta) and (d^2 triangle)/(d theta^2) .

If an arc of length l of a circle of radius r subtends an angle theta radians at the centre what is the relation connecting l , r , theta

A window is in the form of a rectangle surmounted by a semicircle as shown in the figure. If r is the radius of the semicircle and x is the length of the larger side of the rectangleThe perimeter of the window is 5 metres Find the area of the window in terms of r.

Rectangles are inscribed inside a semi-circle of radius r. Find the rectangle with maximum area.

A window is in the form of a rectangle surmounted by a semicircle as shown in the figure. The perimeter of the window is 5 metres. If r is the radius of the semicircle and x is the length of the larger side of the rectangle, find a relation between r,x.

Let a and b be the intercepts made by a line on the x-axes and y-axes respectively.If the area of the triangle formed by the coordinate axis and the line is 6 square units and length of the hypotenuse is 5 units. Prove that the equation of the line is 3x + 4y = 12 or 3x + 4y = -12 or 4x + 3y = 12 or - 4x - 3y = 12