An open box of maximum value is to be made from a square piece of tin sheet 24 cm on a side by cutting equal squares from the corners and turning of the sides.
Complete the following table.

An open box of maximum volume is to be made from a square piece of tin sheet 24 cm on a side by cutting equal squares from the corners and turning of the sides. Using the table, express V as a function of x and determine its domain.

A square piece of tin of side 18 cm is to be made into a box without top by cutting a square from each corner and folding up the flaps to from the box. What should be the side of the square to be cut off so that the volume of the box is maximum?

A rectangle sheet of tin with adjacent sides 45 cm and 24 cm is to be made into a box without top, by cutting off equal squares from the corners the folding up the flaps. Taking the side of the square cut off as x, express the volume of the box as the function of x.

An rectangle sheet of tin with adjascent sides 45 cm and 24 cm is to be made into a box without top, by cutting off equal squares of side x from the corners the folding up the flaps. For what value of x, the volume of the box will be maximum.

The pictures shows a tangram of 7 pieces made by cutting a square of side 4 centimetres. Calculate the length of the sides of each piece.

Corners of a square are. on a circle. If the length of one side of square is 10 cm, find the perimeter of the circle.

An open box is made by removing squares of equal size from the corners of a tin sheet of size 16cmxx10cm and folding up the sides of the box so obtained. What is the value of x for which V is maximum?

An open box is made by removing squares of equal size from the corners of a tin sheet of size 16cmxx10cm and folding up the sides of the box so obtained. With the help of figure, obtain the relation V=x(16-2x)(10-2x).