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JMD PUBLICATION-INVERSE TRIGONOMETRIC FUNCTIONS-EXAMPLE
- Range of function cos^-1 x is :
02:19
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- Write the value of sin^-1 x + cos^-1 x from the following :
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- Select the correct answer :sin(cos^-1x+tan^-1x) =
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- Select the correct answer :Principal value of tan^- √3 =
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- Principal value of sin^-1 (-frac{ 3}{2}) is :
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- Principal value of cos^-1 (-frac{1}{2}) is :
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- Select the correct answer : cos^-1 (1/2) +2sin^-1(1/2)
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- tan^-1(frac{1}{sqrt3}) - sin^-1(frac{1}{2}) is equal to :
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- Select the correct answer :sin^-1(sin2π/3)
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- Select the correct answer :sin(cos^-1x) =
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- Range of function tan^-1 x is :
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- Domain of the function f (x) = sin^-1 x is equal to :
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- Principal value of cos^-1 (-frac{1}{2}) is :
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- Find the value of tan(sin^-1 frac{3}{5} + cot^-1 frac{3}{2}).
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- Principal value of cos^-1 (-frac{1}{2}) is :
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- Find dy/dx when: y= tan^-1((2x)/(1-x^2))
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- Prove that tan^(-1)sqrtx = 1/2cos^(-1) ((1-x)/(1+x)), x in [0,1]
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- Prove that sqrt((1+sinA)/(1-sinA))=(1+sinA)/cosA .
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- Show that : tan^-1 frac{1}{3} + tan^-1 frac{1}{5}=frac{1}{2} cos^-1 fr...
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- Prove that : tan^(-1) (1) + tan ^-1 (2) + tan^(-1) (3) = pi1
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