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Find lambda so that the scalar projectio...

Find lambda so that the scalar projection of `veca=lambdahati+hatj+4hatk` on `vecb=2hati+6hatj+3hatk` is 4units

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Find the scalar projection of : veca=7hati+hatj-4hatk on vecb=2hati+6hatj+3hatk .

Find the scalar projection of : veca=3hati-2hatj+hatk on vecb=hati-2hatj-3hatk .

Find the scalar projection of : veca=7hati+3hatj+6hatk on vecb=5hati-2hatj+3hatk .

Find the scalar projection of : veca=2hati-hatj-3hatk on vecb=3hati-5hatj+hatk .

Find the scalar projection of : veca=2hati+3hatj+2hatk on vecb=hati+2hatj+hatk .

Find the scalar projection of : veca=hati+3hatj+7hatk on vecb=7hati-hatj+8hatk .

The projection of veca=2hati-2hatj-hatk on vecb=3hati-hatj+2hatk is equal to:

JMD PUBLICATION-SOLVED SAMPLE QUESTION PAPERS-EXAMPLE
  1. solve 'int0^(π/4)sqrt(1+sin2xdx)'

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  2. find the area of the region bounded by 'y^2=4x' and x=2

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  3. Find lambda so that the scalar projection of veca=lambdahati+hatj+4hat...

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  4. Find unit vector in the direction of veca+vecb, where veca=-hati+hatj+...

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  5. Prove that : tan^-1[(sqrt(1+x^2) - sqrt(1-x^2))/(sqrt1+x^2 + sqrt(1-x^...

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  6. If x^y+y^x= (x+y)^(x+y), then prove that dy/dx= ((x+y)^(x+y) [1+log(x+...

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  7. If y= [Log(x+sqrt(x^2+1))]^2 then show that (x^2+1)y2+xy1=0

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  8. Evaluate intdx/(sinx-sin2x)

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  9. Solve (3xy+y^2)dx+(x^2+xy)dy=0, y(1)=1

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  10. solve the differential equation: dy/dx=tan(x+y)

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  11. A car manufacturing factory has to plant s X and Y. Plan X manufacture...

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  12. Solve the following system of linear equations by matrix method: x - y...

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  13. If A= [[1,2,2,],[2,1,2,],[2,2,1,]] then verify A^-1A=I

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  14. Find the shortest distance (S.D.) between the lines : vec r = hat i + ...

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  15. Find the equation of the perpendicular drawn from the point (2,4,-1) t...

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  16. Maximise z=20x+15y subject to constraints 120x +60yle12000,x+yle150

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  17. Maximise z=x+y subject to 2x+yle50, x+2y=40

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  18. The number of bijective functions from A to B if n(A)=n(B)=4

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  19. The value of sin(cos^-1(3/5)) is:

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  20. If AB=A and BA=B, then B^2=

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