Solve : `cot^-1(2x)+cot^-1(3x)=pi/4`

Solve int 2cot^2x dx

Prove that cot^-1(13) + cot^-1(21) + cot^-1 (-8) = pi

Solve the following equations. cot^-1 x - cot^-1 (x+2) = pi/12, x > 0

find the value of x: cos(tan^-1x) = sin(cot^-1(3)/(4))

Prove that cot^-1x+cot^(-1)(1/x) is a constant.

cot^-1(-x) = pi - cot^-1x , x in R

Solve (tan^(-1) x)^(2) + (cot^(-1) x)^(2) = (5pi^(2))/(8)

Find the value of cosec { cot( cot^(-1).(3pi)/4)}

The value of cot (tan^-1 x + cot^-1 x) is equal to :

If A = 1/1 cot ^(-1) (1/1) + 1/2 cot^(-1) (1/2) + 1/3 cot ^(-1) ( 1/3) " and " B = 1 cot^(-1) ( 1) + 2 cot^(-1) (2) + 3 cot^(-1) (3) " then " |B - A| " is equal to " (a pi )/b + c/d cot ^(-1) (3) where a,b,c,d in N are in their lowest form , find ( b -a - c - d)